# How do you solve using the quadratic formula method 2x^2 + 3x – 1 = 0?

Mar 7, 2016

$x = \frac{- 3 + \sqrt{17}}{4}$ or $x = \frac{- 3 - \sqrt{17}}{4}$

#### Explanation:

Quadratic formula which gives solution of $a {x}^{2} + b x + c = 0$
is $x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$.

In the equation 2x^2+3x–1=0, $a = 2$, $b = 3$ and $c = - 1$ and hence solution is

$x = \frac{- 3 \pm \sqrt{{3}^{2} - 4 \times 2 \times \left(- 1\right)}}{2 \times 2}$

or $x = \frac{- 3 \pm \sqrt{9 + 8}}{2 \times 2} = - \frac{3 \pm \sqrt{17}}{4}$

i.e. $x = \frac{- 3 + \sqrt{17}}{4}$ or $x = \frac{- 3 - \sqrt{17}}{4}$