How do you solve w(6w+1)=2?

Mar 15, 2016

First distribute the parentheses.

Explanation:

$6 {w}^{2} + w = 2$

$6 {w}^{2} + w - 2 = 0$

$6 {w}^{2} + 4 w - 3 w - 2 = 0$

$2 w \left(3 w + 2\right) - 1 \left(3 w + 2\right) = 0$

$\left(2 w - 1\right) \left(3 w + 2\right) = 0$

$w = \frac{1}{2} \mathmr{and} - \frac{2}{3}$

Hopefully this helps!