How do you solve $\frac{w}{7} + 3 = - 1$ $w/7+3=-1$ ?

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Answer 1 · 2017-01-21T20:05:05

See the entire solution process below;

First, subtract $3$ $color(red)(3)$ from each side of the equation to isolate the $w$ $w$ term and keep the equation balanced:

$\frac{w}{7} + 3 - 3 = - 1 - 3$ $w/7 + 3 - color(red)(3) = -1 - color(red)(3)$

$\frac{w}{7} + 0 = - 4$ $w/7 + 0 = -4$

$\frac{w}{7} = - 4$ $w/7 = -4$

Now, multiply each side of the equation by $7$ $color(red)(7)$ to solve for $w$ $w$ while keeping the equation balanced:

$\frac{w}{7} \times 7 = - 4 \times 7$ $w/7 xx color(red)(7) = -4 xx color(red)(7)$

$w/color(red)(cancel(color(black)(7))) xx cancel(color(red)(7)) = -28$

$w = -28$

How do you solve w/7+3=-1w7+3=−1w/7+3=-1?