# How do you solve x^(-1/2)=5?

Oct 17, 2015

$x = \frac{1}{25}$

#### Explanation:

Raise ${x}^{- \frac{1}{2}}$ to $- 2$ to cancel out the exponents.

$\left[1\right] \textcolor{w h i t e}{X X} {x}^{- \frac{1}{2}} = 5$

$\left[2\right] \textcolor{w h i t e}{X X} {\left({x}^{- \frac{1}{2}}\right)}^{-} 2 = {\left(5\right)}^{-} 2$

$\left[3\right] \textcolor{w h i t e}{X X} x = {\left(5\right)}^{-} 2$

$\left[3\right] \textcolor{w h i t e}{X X} x = {\left(\frac{1}{5}\right)}^{2}$

$\left[4\right] \textcolor{w h i t e}{X X} \textcolor{red}{x = \frac{1}{25}}$