How do you solve #x= 1+ 5\sqrt { x - 5}#?
1 Answer
Dec 2, 2016
Explanation:
Isolate the
#x- 1 = 5sqrt(x- 5)#
#(x- 1)^2 = (5sqrt(x- 5))^2#
#x^2 - 2x + 1 = 25(x - 5)#
#x^2 - 2x + 1 = 25x - 125#
#x^2 - 27x + 126 = 0#
#(x - 21)(x - 6)= 0#
#x = 21 or 6#
Checking in the original equation, you will find both solutions work.
Hopefully this helps!
