# How do you solve #(x+1)/(x-1)=2/(2x-1)+2/(x-1)#?

##### 1 Answer

#### Explanation:

We have an equation,

For simplicity, which you might find to your liking, I'll be taking

(Note, 2x-1=x+x-1=x+y)

Now, we have two terms, one on either side of the equation to have the same denominator, being

so what I'll be doing is that I'll subtract on both sides by

Since the terms on the left-hand side already had the same denominator, I already grouped them together.

By solving the sum on the numerator of the left-hand side, we get

Now, what is the numerator of the left-hand side similar to? If you go back up to the top of the answer, you'll see that I equated

So that makes the left-hand side of the equation as

Multiplying by

Now, we know that

I'm sure it'll be easy to find the answer now.