How do you solve #x+ (-11) = 5#?

1 Answer
seol
Nov 27, 2016

#x=16#

Explanation:

equation given
solve #x+(-11)=5#

concept application
subtracting a negative number #a-(-b)=a+b# because it is like adding a product of #-1# and #-b#, which is positive #b# #\rArra+(-1)(-b)=a+b#

calculation
add #(-11)# to both sides #\rArrx\cancel(+(-11))\cancel(\color(red)(-(-11)))=5\color(red)(-(-11))#
now you have #x=5-(-11)#
subtracting negative number #\rArrx=5\color(fuchsia)(+)11=16#

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