How do you solve #(x - 13) ^ { 2} = 45#?

2 Answers
Jun 17, 2018

Answer:

#x=+-sqrt(45) + 13#

Explanation:

We want to find the value of x, so we try to isolate.
we can take the square root of both sides which removes the squared from the brackets.

#sqrt((x-13)^2) = +-sqrt(45)#
#x-13 = +-sqrt(45)#

Then we just add 13 to both sides and we are left with

#x = +-sqrt(45) + 13#

Jun 17, 2018

Answer:

Take square root and rearrange to get the two answers

Explanation:

#(x-13)^2=45#

Take square root:
#x-13=+-sqrt(45)=+-3sqrt(5)#

#x=13+-3sqrt(5)#