# How do you solve x^2+10=11?

Oct 15, 2015

$\pm 1$

#### Explanation:

Subtract $10$ form both sides

${x}^{2} + 10 - 10 = 11 - 10$

${x}^{2} = 1$

Take the square root of both sides

$\sqrt{{x}^{2}} = \pm \sqrt{1}$

$x = \pm 1$

Remember we have to have plus or minus $1$ because
${1}^{2} = 1$ and ${\left(- 1\right)}^{2} = 1$