How do you solve #x^2 - 10x + 21= 0# graphically?
2 Answers
Jun 12, 2017
The graph is given below
Explanation:
Here it is graph{(x^2)-(10x)+21 [-3.705, 16.295, -5.055, 4.945]}
Note that at
Jun 12, 2017
Explanation:
#"from the graph of " x^2-10x+21#
graph{x^2-10x+21 [-10, 10, -5, 5]}
#"the solution to "#
#x^2-10x+21=0" are the values of x where the"#
#"graph crosses the x-axis"#
#rArrx=3" or " x=7#
#color(blue)"As a check"#
#"Substitute these values into " x^2-10x+21#
#x=3to9-30+21=0larrcolor(red)" True"#
#x=7to49-70+21=0larrcolor(red)"True"#