How do you solve #x^2-10x=-24# by graphing?

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Answer 1 · 2018-07-21T20:20:29

#x=4, x=6#

Well, you set it equal to #0#:
#x^2-10x+24#

Graph it:
graph{x^2-10x+24 [-10, 10, -5, 5]}

Tips on determining the vertex:
#x=-b/(2a)#

For the y-coordinate, plug the x-coordinate into the equation and solve for #y#

Write the equation in the vertex form:
#y=a(x-h)^2+k#
Where #(h,k)# is the vertex

#y=(x-5)^2-1#, so essentially graph the parent quadratic function #y=x^2#, 5 units to the right and one unit down

Look at the zeroes or x-intercepts:
#x=4 and 6#