# How do you solve x^2 - 12x + 36 = 25 by completing the square?

${x}^{2} - 12 x + 36 = 25$
or, ${x}^{2} - 2 \cdot 6 \cdot x + {\left(6\right)}^{2} = 25$
or, ${\left(x - 6\right)}^{2} = {5}^{2}$
either, $x - 6 = 5$ or, $x - 6 = - 5$
so,$x = 11$ or, $x = 1$