Question

How do you solve `x^ { 2} + 14x = - 13`?

Answer 1

You can start by adding `13` to both sides, so the right part will be `0`

Explanation:

`->x^2+14x+13=0`

We now need to factorize `13` into two factors that add up to `14`
These will be `+1and+13`

Now:
`(x+1)(x+13)=0->`

`(x+1)=0->x=-1or`
`(x+13)=0->x=-13`