# How do you solve x^2-14x+45=0 by completing the square?

May 3, 2015

${x}^{2} - 14 x + 45 = 0$

$\left({x}^{2} - 14 x + {7}^{2}\right) - {7}^{2} + 45 = 0$

${\left(x - 7\right)}^{2} = 4$

$x - 7 = \pm 2$

$x = 7 \pm 2$

$x = 9$ or $x = 5$