# How do you solve x^2-16x+48=0?

Nov 20, 2015

By factoring the expression on the left side of the equation we get
$x = 4$ or $x = 12$

#### Explanation:

Given ${x}^{2} - 16 x + 48 = 0$

Factoring:
$\textcolor{w h i t e}{\text{XXX}} \left(x - 4\right) \left(x - 12\right) = 0$

Either
$\textcolor{w h i t e}{\text{XXX}} \left(x - 4\right) = 0 \Rightarrow x = 4$
or
$\textcolor{w h i t e}{\text{XXX}} \left(x - 12\right) = 0 \Rightarrow x = 12$