Question

How do you solve `x^2-16x+48=0`?

Answer 1

By factoring the expression on the left side of the equation we get
`x=4` or `x=12`

Explanation:

Given `x^2-16x+48=0`

Factoring:
`color(white)("XXX")(x-4)(x-12)=0`

Either
`color(white)("XXX")(x-4)=0 rArr x=4`
or
`color(white)("XXX")(x-12)=0 rArr x=12`