# How do you solve (X-2)^2=12?

$x - 2$ must be plus or minus the root of $12$
$x - 2 = \pm \sqrt{12} \to$add $2$ on both sides:
$x = 2 \pm \sqrt{12} \to$ can be simplified to:
$x = 2 \pm 2 \sqrt{3}$