# How do you solve  (x + 2)^2 = 16?

Apr 22, 2018

$x = 2$ or $x = - 6$

#### Explanation:

Get rid of the square by square rooting both sides:
$\sqrt{{\left(x + 2\right)}^{2}}$ = ± sqrt(16)

The square root cancels the square:

$x + 2$ = ± sqrt(16)

± sqrt(16)=+4 or -4

So you have to solve for both $+ 4$ and $- 4$

$x + 2 = 4$

$x = 2$

and

$x + 2 = - 4$

$x = - 6$