# How do you solve |x+2|>2?

Apr 8, 2016

x > 0 and x < $- 4$. The graduation x on the real line, under this condition, is outside the closed interval $\left[- 4 , 0\right]$.
$| x + 2 | > 2$ is equivalent to the pair of inequalities
$x + 2 > 2 \mathmr{and} - \left(x + 2\right) > 2$.
So, x > 0 and (rearranging for +x) $x < - 4$.