Question

How do you solve `(x+2)^2=36`?

Answer 1

`x=-8` or `x=4`

Explanation:

`(x+2)^2=36`

expanding the left side:
`rArrcolor(white)("XX")x^2+4x+4=36`

subtracting `36` from both sides:
`rArrcolor(white)("XX")x^2+4x-32=0`

factoring
`rArrcolor(white)("XX")(x+8)(x-4)=0`

one of the two factors must be zero
#rArrcolor(white)("XX"){:((x+8)=0,color(white)("xx")"or"color(white)("xx"),(x-4)=0), (x=-8,,x=4) :}#