# How do you solve x^2 - 20x + 100 = 36?

Mar 24, 2018

See below

#### Explanation:

We have, ${x}^{2} - 20 x + 100 - 36 = 0$

Or, ${x}^{2} - 20 x + 64 = 0$

Carrying out middle-term factorization,we get,

${x}^{2} - 16 x - 4 x + 64 = 0$

$x \left(x - 16\right) - 4 \left(x - 16\right) = 0$

$\left(x - 16\right) \left(x - 4\right) = 0$

Thus,the two solutions of $x$ which we get are $x = 16 , 4$