How do you solve #x ^ { 2} - 24x + 144= 36#?

1 Answer
Apr 1, 2017

Factor or quadratic formula. Factoring works fine in this example. As a result, you get #6# and #18#.

Explanation:

So solving a quadratic equation implies that we are solving for #x# - the zeros/roots/solutions.

There are two main ways to do this:

  1. Factoring (from standard).
  2. Quadratic formula (from standard).

If #x^2 - 24x + 144 = 36#, then we would have to bring over #36# to the "other side", and then equate the equation to the #0#.

#x^2 - 24x + 144 = 36#

#x^2 - 24x + 144 - 36 = 0#

#x^2 - 24x + 108 = 0#

Now, this is a simple trinomial. So let's see if we can factor it normally: "what two numbers added equals #b#, and multiplied equals #ac?"

We see that #-18# and #-6# works perfectly. Therefore, we get:

#(x-6)(x-18) = 0#

Isolate the #x# in their respective brackets and the solutions are #6# and #18#.

Hope this helps :)