How do you solve #x^2-2x-14=0# by completing the square?
First, you have to move the 14 to the other side by adding it :
To complete the square you divide the term with one x by 2 and then take that number and square it :
We then take that 1 and add it to both sides of the equation :
Now we can factor the left side of the equation :
Take the square root of both sides to get rid of the square on the left hand side (be sure to add the
which then equals...
Now get x by itself :