How do you solve # x^2 + 2x - 3 = 0#?

1 Answer
Apr 4, 2018

Answer:

#x = -3#, #x = 1#

Here's how I did it:

Explanation:

To solve for #x#, we factor it.
To factor this, you have to find two numbers that multiply up to #-3# and add up to #2#.

These two numbers are #3# and #-1#:
#3 * -1 = -3#
#3 - 1 = 2#

Now we put the equation like this:
#(x+3)(x-1) = 0#

#x+3 = 0 -> x = -3#

#x - 1 = 0 -> x = 1#