Question

How do you solve `x^2 + 2x - 3 = 0`?

Answer 1

`x = -3`, `x = 1`

Here's how I did it:

Explanation:

To solve for `x`, we factor it.
To factor this, you have to find two numbers that multiply up to `-3` and add up to `2`.

These two numbers are `3` and `-1`:
`3 * -1 = -3`
`3 - 1 = 2`

Now we put the equation like this:
`(x+3)(x-1) = 0`

`x+3 = 0 -> x = -3`

`x - 1 = 0 -> x = 1`