# How do you solve x^2+2x-3=0 by completing the square?

May 5, 2015

${x}^{2} + 2 x - 3 = 0$

If ${x}^{2} + 2 x + {a}^{2}$ is a square then ${a}^{2} = 1$

${x}^{2} + 2 x + 1 - 1 - 3 = 0$

${\left(x + 1\right)}^{2} = 4$

$x + 1 = \pm \sqrt{4}$

$x = - 1 \pm 2$

$x = - 3 \text{ or } x = 1$