Question

How do you solve `x^2+2x-3=0` graphically?

Answer 1

Find the points at which the parabola `y=x^2+2x-3` cuts the x-axis y = 0.-

Explanation:

`(x+1)^2=y+4`
The axis of this parabola is `x=-1`
The vertex is `(-1, -4)`,
The parabola cuts the x-axis y = 0 at x = 1 and `x = -3`.