How do you solve x^2-2x=5 using the quadratic formula?

Answer:

$x = 4$ and $x = 0$

Explanation:

In quadratic equations we have a formulae to find the roots of the quadratic expression $a {x}^{2} + b x + c = 0$ that is:
$x = \frac{\left(- b\right) \pm \left(\sqrt{{b}^{2} - 4 a c}\right)}{2 a}$
So extracting the values from the given above equation and substituting we get
$x = \frac{- \left(- 2\right) \pm \left(\sqrt{\left({\left(- 2\right)}^{2}\right) - 4 \left(1\right) \left(- 5\right)}\right)}{2 \left(1\right)}$
$x = \frac{2 - 2}{2}$,$x = \frac{2 + 2}{2}$
$\implies x = 4 , 0$