How do you solve #x^2-2x=5# using the quadratic formula?

1 Answer

Answer:

#x=4# and #x=0#

Explanation:

In quadratic equations we have a formulae to find the roots of the quadratic expression #ax^2+bx+c=0# that is:
#x=[(-b)+-(sqrt(b^2-4ac))]/(2a)#
So extracting the values from the given above equation and substituting we get
#x=[-(-2)+-(sqrt(((-2)^2)-4(1)(-5)))]/[2(1)]#
#x=(2-2)/2#,#x=(2+2)/2#
#=>x=4,0#