How do you solve #x^2-2x-8=0# graphically?

1 Answer
Sep 6, 2016

#x = -2 " or "x = 4#

Explanation:

First you need to have a graph to be able to use it.

It will be a parabola which you can obtain by plotting points.
The equation of the graph of the parabola is

#y = x^2 -2x-8#

Now compare the equation we are asked to solve with the equation of the parabola...
#x^2 -2x-8 = color(red)(y)#
#x^2 -2x-8 = color(red)(0)#

We can see that #color(red)(y)# has been replaced by #color(red)(0)#

#y = 0# is the equation of the x-axis.

In other words the question is asking all of the following questions - different ways of asking the same thing.

"Where does the parabola cross the x-axis?"
"What are the x-intercepts?"
"What are the roots of the equation"
"Solve the equation" #x^2 -2x+8 = 0#

Read the two values off the graph to solve the equation.
#x = -2 " or "x = 4#

graph{x^2-2x-8 [-6.82, 13.18, -9.16, 0.84]}