How do you solve #x^2 3^x -8(3^x)= 0#?
1 Answer
Apr 21, 2018
Explanation:
#"factor out "3^x#
#rArr3^x(x^2-8)=0#
#"equate each factor to zero and solve for x"#
#"note that "3^x!=0#
#rArrx^2-8=0rArrx^2=8rArrx=+-2sqrt2" is the solution"#
