Question

How do you solve `x^2+3x+1=0` algebraically?

Answer 1

`x=(-3+sqrt5)/2 orx=(-3-sqrt5)/2`

Explanation:

`x^2+3x+1=0 or x^2+3x+9/4 -9/4+1=0 or (x+3/2)^2 -5/4=0 or (x+3/2)^2 =5/4 or x+3/2 = +-sqrt5/2 or x= -3/2+-sqrt5/2 :. x=(-3+sqrt5)/2 orx=(-3-sqrt5)/2` {Ans]