# How do you solve x^2-3x=-10 by completing the square?

##### 1 Answer
May 28, 2015

${x}^{2} - 3 x = - 10$

${x}^{2} - 4 x + 4 = - x - 6$

${\left(x - 2\right)}^{2} = - x - 6$

$x - 2 = \sqrt{- x - 6}$

No real solutions, because you can't have the square root of a negative number.