# How do you solve x^2-3x=-10 by completing the square?

${x}^{2} - 3 x = - 10$
${x}^{2} - 4 x + 4 = - x - 6$
${\left(x - 2\right)}^{2} = - x - 6$
$x - 2 = \sqrt{- x - 6}$