How do you solve #x^2 + 3x = 10# by factoring?

1 Answer
Roella W.
Jan 5, 2016

#(x +2)(x-5)=0#

Explanation:

First arrange all the elements on one side
#x^2 +3x - 10 = 0#
Then, knowing that (ax+b)(cx+d)# gives ##acx^2 +(ad+bc)x + bd#
we look for factors of 1 (the coefficient of #x^2#) and #10# that subttract to give 3 (the middle term and the last term have different signs so the result must be found by subtraction).
#10 = 5*2# and #5-2 = 3# so the result is
#(x +2)(x-5)=0#

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