# How do you solve x^2-3x+2=0 using the quadratic formula?

${x}_{1} = 2 \mathmr{and} {x}_{2} = 1$
${x}^{2} + p x + q = 0$
${x}_{1 , 2} = - \frac{p}{2} \pm \sqrt{{\left(\frac{p}{2}\right)}^{2} - q}$
$p = - 3 \mathmr{and} q = 2$
${x}_{1 , 2} = \frac{3}{2} \pm \sqrt{\frac{9}{4} - 2}$
${x}_{1} = \frac{3}{2} + \frac{1}{2} = 2 \mathmr{and} {x}_{2} = \frac{3}{2} - \frac{1}{2} = 1$