# How do you solve x^2+3x+2 by completing the square?

The answer is $x = - 1$ and $x = - 2$
${x}^{2} + 4 x + 4 - x - 2 = 0 \implies {\left(x + 2\right)}^{2} - \left(x + 2\right) = 0$
So you know one answer is $x = - 2$
Now you can divide the polynomial by its factor $\left(x + 2\right)$ and you have
$x + 2 - 1 = 0 \implies x = - 1$