How do you solve #x^2+3x-4=0# graphically?

1 Answer
Aug 30, 2017

See below.

Explanation:

Plot the points generated by the function #y = x^2 + 3x -4#.

Where the parabola crosses or turns at the #x# axis is the solution to the equation # x^2 + 3x -4 = 0#.

In this example the parabola crosses the #x# axis at the points #x = -4# and #x = 1# , so this is the solution to the equation.
See graph:

graph{x^2 +3x -4 [-16.02, 16.01, -8.01, 8.01]}