How do you solve #x/2=(3x)/4+5#?

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Answer 1 · 2016-01-16T16:22:58

#x/2=(3x)/4+5#

Multiply both sides by #color(red)4#.

#implies color(red)4(x/2)=color(red)4((3x)/4+5)#

#implies color(red)4(x/2)=color(red)4*(3x)/4+color(red)4*5#

#implies 2x=3x+20#

Subtract #color(purple)(2x)# from both sides.

#implies 2x-color(purple)(2x)=3x+20-color(purple)(2x)#

#implies 0=x+20#

Subtract #color (blue)20# from both sides.

#implies 0-color(blue)20=x+20-color(blue)20#

#implies -20=x#
#implies x=-20#