# How do you solve x^2+3x-6=0?

Jul 3, 2017

Find the zeros.

#### Explanation:

Solving implies we find the value(s) of $x$. This means we find the zeros of the function.

This equation is in standard form, so we have two methods to determining the value of $x$: complete the square or use the quadratic formula.

I will be using the quadratic formula because it's less confusing.

All we have to do is equate the equation to $0$ (it's already done to us) and sub in the values accordingly. Then we solve.

$\frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

$= \frac{- \left[3\right] \pm \sqrt{{\left[3\right]}^{2} - 4 \left[1\right] \left[- 6\right]}}{2 \left[1\right]}$

We simplify.

$= \frac{- 3 \pm \sqrt{33}}{2}$

Now we solve.

$x \left[+\right] = 1.372281323$

$\cong 1.37$

$x \left[-\right] = - 4.372281323$

$\cong - 4.37$

Therefore, the zeros are $1.37$ and $- 4.37$.

Here is a graph for reference.

graph{y=x^2 + 3x -6 [-20.27, 20.28, -10.14, 10.13]}

Hope this helps :)