# How do you solve x^2 + 3x - (7/4) = 0 by completing the square?

Apr 12, 2018

$x = - 1.5 \pm 2$

#### Explanation:

x^2+3x−7/4=0

${\left(x + \frac{3}{2}\right)}^{2} - {\left(\frac{3}{2}\right)}^{2} - \frac{7}{4} = 0$

${\left(x + \frac{3}{2}\right)}^{2} - \frac{9}{4} - \frac{7}{4} = 0$

${\left(x + \frac{3}{2}\right)}^{2} - \frac{16}{4} = 0$

${\left(x + \frac{3}{2}\right)}^{2} = 4$

$x + \frac{3}{2} = \sqrt{4}$

$\textcolor{red}{x = - \frac{3}{2} \pm 2}$

$\textcolor{red}{x = 0.5 \mathmr{and} x = - 3.5}$