# How do you solve x^2-4x=0?

${x}^{2} - 4 x = x \cdot \left(4 - x\right)$
Now,the roots of this equation are 0 as $0 \cdot \left(4 - 0\right) = 0$ and 4 as $4 \cdot \left(4 - 4\right) = 0$