# How do you solve x^2 + 4x = 0 by completing the square?

Aug 9, 2016

$x = 0 \mathmr{and} x = - 4$

#### Explanation:

${x}^{2} + 4 x = 0 \mathmr{and} {\left(x + 2\right)}^{2} - 4 = 0 \mathmr{and} {\left(x + 2\right)}^{2} = 4 \mathmr{and} \left(x + 2\right) = \pm 2 \mathmr{and} x = - 2 \pm 2 \therefore x = 0 \mathmr{and} x = - 4$[Ans]