How do you solve #x^2 + 4x + 1 = 0# using the quadratic formula?
1 Answer
Mar 11, 2018
Explanation:
#"Given the quadratic equation in standard form"#
#•color(white)(x)ax^2+bx+c=0 color(white)(x);a!=0#
#"We can solve for x using the "color(blue)"quadratic formula"#
#•color(white)(x)x=(-b+-sqrt(b^2-4ac))/(2a)#
#x^2+4x+1=0" is in standard form"#
#"with "a=1,b=4" and "c=1#
#rArrx=(-4+-sqrt(16-4))/2=(-4+-sqrt12)/2#
#color(white)(x)=(-4+-2sqrt3)/2=-2+-sqrt3larrcolor(red)"exact values"#
