# How do you solve x^2+4x+2=0 by factoring?

${x}^{2} + 4 x + 2 = \left(x + 2 + \sqrt{2}\right) \cdot \left(x + 2 - \sqrt{2}\right)$
therefore ${x}^{2} + 4 x + 2 = 0$
$\rightarrow x = - 2 - \sqrt{2} \text{ or } x = - 2 + \sqrt{2}$
$\textcolor{w h i t e}{\text{XXXX}} x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$