Question

How do you solve `x^2+4x-5=0` by completing the square?

Answer 1

`x=-5 ; x=1`

Explanation:

`x^2+4x-5 =0 or x^2+4x+4-9=0 or(x+2)^2-3^2=0 or(x+2+3)(x+2-3)=0 or(x+5)(x-1)=0`So either `x+5=0 ; x=-5 or x-1=0 ; x=1`[Ans]