# How do you solve x^2 + 5 = 41?

May 13, 2018

$x = 6$

#### Explanation:

${x}^{2} + 5 = 41$

${x}^{2} = 36$

$\pm {6}^{2} = 36$

$x = \pm 6$

hope this helps

$x = \pm 6$

#### Explanation:

${x}^{2} + 5 = 41$

${x}^{2} + 5 \textcolor{red}{- 5} = 41 \textcolor{red}{- 5}$

${x}^{2} = 36$

$\sqrt{{x}^{2}} = \sqrt{36}$

$x = \pm 6$

We can graph both the right and left hand sides:

graph{(y-x^2-5)(y-0x-41)=0 [-11.31, 12.99, 32.25, 44.41]}