How do you solve x^2 = 5x +2?

Jul 19, 2016

$x = \frac{10 + \sqrt{33}}{2} , \frac{10 - \sqrt{33}}{2}$

Explanation:

${x}^{2} - 5 x - 2 = 0$

then use the qudratic formula

$x = 5 \pm \frac{\sqrt{{5}^{2} - \left(4 \cdot 1 \cdot - 2\right)}}{2 \cdot 1}$
$x = 5 \pm \frac{\sqrt{33}}{2}$
$x = \frac{10 + \sqrt{33}}{2} , \frac{10 - \sqrt{33}}{2}$