# How do you solve x^2 – 5x – 3 = -7 using the quadratic formula?

Jan 19, 2017

$x = 1$ or $x = 4$

#### Explanation:

${x}^{2} - 5 x - 3 = - 7$

Add $7$ to each side.

${x}^{2} - 5 x + 4 = 0$

Factorise.

${x}^{2} - 4 x - x + 4 = 0$

$x \left(x - 4\right) - 1 \left(x - 4\right) = 0$

$\left(x - 1\right) \left(x - 4\right) = 0$

$x - 1 = 0$ or $x - 4 = 0$

$x = 1$ or $x = 4$