# How do you solve x^2 - 5x - 6 = 0?

We factor by finding numbers that multiply to $- 6$ and add to $- 5$, of course $- 6$ and $1$ so $0 = {x}^{2} - 5 x - 6 = \left(x - 6\right) \left(x + 1\right)$ so $x = 6$ or $x = - 1.$