# How do you solve  x^2-5x-6=0?

Apr 30, 2016

$x = \textcolor{red}{- 1} , \textcolor{b l u e}{6}$

#### Explanation:

${x}^{2} - 5 x - 6 = 0$

Find two numbers that when added equal $- 5$ and when multiplied equal $- 6$. The numbers $- 6$ and $1$ meet the criteria.

Rewrite the equation in factored form.

$\left(x + 1\right) \left(x - 6\right) = 0$

Set each factor equal to zero and solve for $x$.

color(red)((x+1)=0

color(red)(x=-1

$\textcolor{b l u e}{\left(x - 6\right) = 0}$

color(red)(x=6

$x = \textcolor{red}{- 1} , \textcolor{b l u e}{6}$