# How do you solve #x^2 +5x-7=0#?

##### 1 Answer

May 24, 2016

#### Explanation:

This quadratic equation is in the form

It has discriminant

#Delta = b^2-4ac = 5^2-(4*1*-7) = 25+28 = 53#

So

We can find them using the quadratic formula:

#x = (-b+-sqrt(b^2-4ac))/(2a)#

#=(-b+-sqrt(Delta))/(2a)#

#=(-5+-sqrt(53))/2#