# How do you solve x^2-5x= -9 using the quadratic formula?

Oct 7, 2016

2 complex roots, $x = \frac{5 \pm 3 i}{2}$

#### Explanation:

Original Equation

${x}^{2} - 5 x = - 9 \implies {x}^{2} - 5 x + 9 = 0$

Standard Form of a quadratic equation

$a {x}^{2} + b x + c = 0$

$a = 1$
$b = - 5$
$c = 9$

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

$x = \frac{- \left(- 5\right) \pm \sqrt{{\left(- 5\right)}^{2} - 4 \left(1\right) \left(9\right)}}{2 \left(1\right)}$

$x = \frac{5 \pm \sqrt{25 - 36}}{2}$

$x = \frac{5 \pm \sqrt{- 9}}{2}$

$x = \frac{5 \pm 3 i}{2}$