Question

How do you solve `x^{2} = - 6+ 7x`?

Answer 1

`x = 6 or x=1`

Explanation:

It is a quadratic, make it equal to 0.

`x^2 -7x +6 = 0" "larr` factorize

`(x-6)(x-1) =0" "` factors of 6 which add to 7

If `x - 6 = 0 rarr x =6`
If `x-1 = 0 rarr x = 1`